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Sunday, 8 June 2014

Jawaban Quis Online SPK dengan Metode TOPSIS

No
Nama
C1
C2
C3
C4
1
Joko
3
3
3
2
2
Widodo
3
3
2
2
3
Simamora
4
4
1
1
4
Susilawati
1
4
2
1
5
Dian
2
3
4
2
6
Roma
2
2
4
2
7
Hendro
3
2
3
2
Dengan Nilai Bobot W = {3, 4, 5, 4}

Penyelesaian :
X1=7,21
X2=8,18
X3=7,68
X4=4,69

r11 = 0,416                                            r12 = 0,367
r21 = 0,416                                            r22 = 0,367
r31 = 0,555                                            r32 = 0,489
r41 = 0,139                                            r42 = 0,489
r51 = 0,277                                            r52 = 0,367
r61 = 0,277                                            r62 = 0,244
r71 = 0,416                                            r72 = 0,244

r13 = 0,391                                            r14 = 0,426
r23 = 0,260                                            r24 = 0,426
r33 = 0,130                                            r34 = 0,213
r43 = 0,260                                            r44 = 0,213
r53 = 0,521                                            r54 = 0,426
r63 = 0,521                                            r64 = 0,426
r73 = 0,391                                            r74 = 0,426

dengan matriks r :
          0,416            0,367            0,391               0,426
          0,416            0,367            0,260               0,426
          0,555            0,489            0,130               0,213
r =     0,139            0,489            0,260               0,213
          0,277            0,367            0,521               0,426
          0,277            0,244            0,521               0,426
          0,416            0,244            0,391               0,426

yij = Wi . rij  Dengan bobot {3, 4, 5, 4}
y11 = (3).0,416 = 1,248                        y12 = (4).0,367 = 1,468
y21 = (3).0,416 = 1,248                        y22 = (4).0,367 = 1,468
y31 = (3).0,555 = 1,665                        y32 = (4).0,489 = 1,956
y41 = (3).0,139 = 0,417                        y42 = (4).0,489 = 1,956
y51 = (3).0,277 = 0,831                        y52 = (4).0,367 = 1,468
y61 = (3).0,277 = 0,831                        y62 = (4).0,244 = 0,976
y71 = (3).0,416 = 1,248                        y72 = (4).0,244 = 0,976

y13 = (5).0,391 = 1,955                        y14 = (4).0,426 = 1,704
y23 = (5).0,260 = 1,3                            y24 = (4).0,426 = 1,704
y33 = (5).0,130 = 0,65                          y34 = (4).0,213 = 0,852
y43 = (5).0,260 = 1,3                            y44 = (4).0,213 = 0,852
y53 = (5).0,521 = 2,605                        y54 = (4).0,426 = 1,704
y63 = (5).0,521 = 2,605                        y64 = (4).0,426 = 1,704
y73 = (5).0,391 = 1,955                        y74 = (4).0,426 = 1,704

maka y yang ternormalisasi terbobot yaitu :
            1,248               1,468               1,955            1,704
            1,248               1,468               1,3                1,704
            1,665               1,956               0,65              0,852
y =       0,417               1,956               1,3                0,852
            0,831               1,468               2,605            1,704
            0,831               0,976               2,605            1,704
            1,248               0,976               1,955            1,704

Solusi Ideal Positif (A+)
y+1 = max {1,248 ; 1,248 ; 1,665 ; 0,417 ; 0,831 ; 0,831 ; 1,248}
y+1 = 1,248
y+2 = max {1,468 ; 1,468 ; 1,956 ; 1,956 ; 1,468 ; 0,976 ; 0,976}
y+2 = 1,956
y+3 = min {1,955 ; 1,3 ; 0,65 ; 1,3 ; 2,605 ; 2,605 ; 1,955}
y+3 = 0,65
y+4 = max {1,704 ; 1,704 ; 0,852 ; 0,852 ; 1,704 ; 1,704 ; 1,704}
y+4 = 1,704
A+ = 1,248 ; 1,956 ; 0,65 ; 1,704

Solusi Ideal Negatif (A-)
y-1 = min {1,248 ; 1,248 ; 1,665 ; 0,417 ; 0,831 ; 0,831 ; 1,248}
y-1 = 0,417
y+2 = min {1,468 ; 1,468 ; 1,956 ; 1,956 ; 1,468 ; 0,976 ; 0,976}
y-2 = 0,976
y-3 = max{1,955 ; 1,3 ; 0,65 ; 1,3 ; 2,605 ; 2,605 ; 1,955}
y-3 = 2,605
y-4 = min {1,704 ; 1,704 ; 0,852 ; 0,852 ; 1,704 ; 1,704 ; 1,704}
y-4 = 0,852
      A-   = 0,417 ; 0,976 ; 2,605 ; 0,852

Nilai Beasiswa Alternatif terbobot dengan solusi ideal positif.
D+1 = 1,393
D+2 = 0,813
D+3 = 0,949
D+4 = 1,356
D+5 = 2,058
D+6 = 2,218
D+7 = 1,620

Nilai Beasiswa Alternatif terbobot dengan solusi ideal negatif.
D-1 = 1,442
D-2 = 1,833
D-3 = 2,518
D-4 = 1,632
D-5 = 1,067
D-6 = 0,947
D-7 = 1,356

Niai Preferensi Mahasiswa
V1 = 0,509
V2 = 0,693
V3 = 0,726
V4 = 0,546
V5 = 0,438
V6 = 0,299
V7 = 0,456
Jadi Mahasiswa yang mendapatkan beasiswa adalah Joko, Widodo, Simamora, Susilawati, dan Hendro.

Nah, untuk cara penyelesaian secara lengkap, anda bisa mendownloadnya disini.

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